Solution to 1986 Problem 20


\begin{align*}E = \frac{m c^2}{\sqrt{1 - u^2/c^2}}\end{align*}
We are given that E = 938 \;\mathrm{MeV}\mathrm{/}\mathrm{c}^2 and m c^2 = 494 \;\mathrm{MeV}\mathrm{/}\mathrm{c}^2. Using the approximations E = 1000 \;\mathrm{MeV}\mathrm{/}\mathrm{c}^2 and m c^2 = 500 \;\mathrm{MeV}\mathrm{/}\mathrm{c}^2 in the above formula gives
\begin{align*}\frac{u^2}{c^2} = .75\end{align*}
0.85^2 = .7905 and 0.7^2 = 0.49. Thus, answer (E) is correct.


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